Chemistry, asked by parthrisa8675, 1 year ago

Crystal field stabilization energy for low spin d4 octahedral complex is

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Answered by aqsaahmed19945
20

In case of octahedral complexes , Crystal field stabilization energy of d4 for low spin and high spin complexes are as follows :

High - spin complexes :

t2g ^ 3 eg ^ 1

0.6 Δ o  

Low - spin complexes :

t2g ^ 4 eg ^ 0

1.6 Δ o

Answered by RomeliaThurston
18

Answer: The crystal field stabilization energy for the given complex is -1.6\Delta o+P

Explanation:

The crystal field stabilization energy is the sum of the energies of all the metal ion electrons. For a metal ion having the configuration of t_{2g}^xe_g^y

The formula for CFSE is given by the equation:

CFSE=x(-0.4\Delta o)+y(0.6\Delta o)+zP

where, P is the pairing energy and z is the number of electrons pairs in the configuration.

For the complex having d^4 low spin complex, the configuration will be t_{2g}^4e_g^0

CFSE=4(-0.4\Delta o)+0(0.6\Delta o)+1P\\\\CFSE=-1.6\Delta o+P

Hence, the crystal field stabilization energy for the given complex is -1.6\Delta o+P

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