csa and tsa of frustum
NitishSangwan:
1/3 π×h(r sq + R sq +rR) = volume
πl( R+ r) = csa
π{L(R+r) + (r s.q + R s.q)}
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Answer:
Step-by-step explanation:
CSA of frustum =πl (R+r)
TSA of frustum=πl(R+r)+πR^2+πr^2
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