Question

CsBr has bcc structure with edge length 4.3. The shortest inter ionic distance in between Cs⁺ and Br⁻ is : (a) 3.72 (b) 1.86(c) 7.44 (d) 4.3

Answer 1

rc+ra=3–√2a

∴rc+ra=3–√×4.32

=3.72A∘

Hence answer is (a)

Answer 2

ra+rc=rt3*4.3/2

=3. 72