CsCl crystallizes in a cubic cell that has a Cl- at each corner and Cs at the centre of the unit cell.if the radius of of Cs is 1.69Å and rcl - = 1.81Å, what is the edge length of unit cell?
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we know for simple cubic lattice, rc+ra=a
1.69+1.81=3.5A
1.69+1.81=3.5A
pknavas1997:
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Answer : The edge length of unit cell is,
Solution :
From the given information, we conclude that the CsCl has BCC (body centered cubic unit cell) structure.
The relation between the edge length and radius of unit cell.
where,
a = edge length of unit cell
= radius of cesium cation =
= radius of chloride anion =
Now put all the given values in the above relation, we get the edge length of the unit cell.
Therefore, the edge length of unit cell is,
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