Question

©There are three prime numbers, the product of1st two no es 1891 and the product of last two no.is 7991. Find all the numbers.​

Answer 1

Answer:

Let's assume the prime numbers in given question is "a, b, and c"

Given-

a×b(product of first two prime numbers) = 1891

b×c(product of last two prime numbers) = 7991

Now,

divide (a×b) by (b×c)

ab 1891

---- = --------

bc 7991

a 31

--- = -----

c 131

a×b = 1891

31×b = 1891

b = 1891

--------

31

b = 61

Therefore,

a = 31

b = 61

c = 131

Answer 2

Answer:

Step-by-step explanation: