Question

Cu crystallizes in fcc unit cell with edge length of 495pm. What is the radius of Cu atom ?​

Answer 1

Explanation:

For fcc unit cell :

a = (2√2)*r

r = a/(2√2)

= 495/(2√2) = 175 pm

Answer 2

The radius of the Cu atom is 175cm

Explanation:

• Copper crystallizes in FCC lattice arrangement.
• - As copper is crystallized in FCC, we can say that copper atoms will be there at the corners of the cube as well as at the faces of the cube.
• - Now, we are given the length of the unit cell.
• - We can say that the face diagonal of the cube will be 2√a.

• Cu crystallizes in an fcc unit cell with edge length of 495pm.
• Given, a = 495 pm Radius, r = ?
• For fcc  structure, radius = r  = a 2 √ 2 = 495 2 × √ 2 =a22=4952×2 = 175 cm.
• Radius of Cu atom = 175 p=.a /2 √ 2 = 495 /2 × √ 2 = 175 cm
• Radius of Cu atom  = 175 cm
• #spj2