Cu + HNO3 = Cu(NO₃)2 + NO + H2O
Do it by ion electron method in such a way that I can understand
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Explanation:
Cu+HNO3→Cu(NO3)2+NO+H2O
Ionic equation,
Cu+H++NO3−→Cu2++NO+H2O
1st step: Splitting into two half reactions,
(Oxidationhalfreaction)Cu→Cu2+; (Reductionhalfreaction)NO3−+H+→NO+H2O
2nd step: Adding H+ ions to the side deficient in hydrogen,
Cu→Cu2+;NO3−+4H+→NO+2HO
3rd step: Adding electrons to the side deficient in electrons,
Cu→Cu2++2e; NO3−+4H++3e→NO+2H2O
4th step: Balancing electrons in both half reactions,
3Cu→3Cu2++6e 2NO3−+8H++6e→2NO+4H2O
5th step: Adding both the half reactions,
3Cu+2NO3−+8H+→3Cu2++2NO+4H2O
Converting it into molecular form
3Cu+2NO3−+8H++6NO3−→3Cu2++6NO3−+2NO+4H2O
or
3Cu+8HNO3→3Cu(NO3)2+2NO+4H2O.
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