[Cu(NH3)4]+2 is paramagnetic justify
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Cu=3d₁₀ 4s₁
oxidation state = +2
Cu2+=3d9
in d-orbital ther will be 4 paired & 1 unpaired
here NH3 i s a weak ligand
∴ it will start pairing up from s-orbital
⇒ hybridisation will be sp³
∴ 1 unpaired electron is there
∴ it is paramagnetic
oxidation state = +2
Cu2+=3d9
in d-orbital ther will be 4 paired & 1 unpaired
here NH3 i s a weak ligand
∴ it will start pairing up from s-orbital
⇒ hybridisation will be sp³
∴ 1 unpaired electron is there
∴ it is paramagnetic
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