[Cu(nh3)4]so4.h2o molecular weight calculate
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Cu=63.5g
N=14g
H=3g
=>NH3=17g
=> 4(NH3)= 17×4= 68g
S=32g
O=16g
=> SO4= 32+(16×4)=32+64=96g
H2O=18g
so the required molecular mass will be:
63.5+68+96+18=245.5g
hope it helps you....
☺✌☺
N=14g
H=3g
=>NH3=17g
=> 4(NH3)= 17×4= 68g
S=32g
O=16g
=> SO4= 32+(16×4)=32+64=96g
H2O=18g
so the required molecular mass will be:
63.5+68+96+18=245.5g
hope it helps you....
☺✌☺
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