Question

[cu (NH3)4] So4 -

hybridization of given equations ​

Answer 1

Answer:

Oxidation no. of Cu in [Cu(NH3)4]SO4 is 2. As such it will have electronic configuration. Any one will think now that it should have sp3 hybridization. But there is an exc eption here. NH3 being a very strong field lig and sh ifts the unpaired 3d orbital to the 4p orbital. Now the remaining 3d and 4p orbital will take part in hybridization and the 4 NH3 lig ands will now bond with them. The hybridization as such will be dsp2 .

So, hybridization of Cu(NH₃)₄SO₄ is sp³.