Question

Cu posses fcc structure of its unit cell. If edge length is 362pm find density

Answer 1

Answer:

FCC has 4 atoms in its lattice

Answer 2

Density of Cu possessing fcc structure of its unit cell is =$8.92 g/cm3$

Explanation:

• FCC or fcc (face-centered cubic) is an arrangement in which the atoms are arranged in such a way that they are at the corners and center of each cube face of the cell.
• Here Atoms are considered to touch along face diagonals of 4 atoms in one unit cell.
• The atoms are arranged so that the corners of the cube is arranged with another atom at the cube center.
• Cu possesses the fcc structure of its unit cell
• Given the  length of edge $3.61$×$10^{-8}$  cm or 362pm
• Molecular weight of Cu (M) is =63.5g/mol
• Number of atoms in the unit cell of fcc is Z=4
• density= Z×M/a3×NA
• Substituting the value of Z,M a, N, A in the equation
• =$4$×$63.5$/($3.61$×$10^{-8} )^{3}$×$6.023$×$10^{23}$
• =$8.92 g/cm3$
• We get the value of density as $8.92 g/cm3$

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