Cu + xHNO, → Cu(NO3)2 + yNO, + 2H,0
The values of x and y are -
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Answer:
The Cu(NO3)2 is an ionic compound with overall oxidation number “0”. Therefore we know that sum of all the oxidation number of Cu, N and O is equal to 0. The first step is jot down the charges of the elements since it is an ionic bond. Cu=+2, N=+5, O=-2.
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4 and 3
Explanation:
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