Question

cu2cl2+hclo gives cl-+cu2+​

Answer 1

$\tt \huge{Answer}$

Cu2Cl2 (s) + HClO (aq) + H+(aq)-------> Cl- (aq) + Cu2+ (aq) + H2O(l)

Copper in Cu2Cl2 (s) in +1 oxidation state

ionic half reactions are as follows

reduction half reaction

ClO-(aq) + 2H+(aq) + 2e----------> Cl-(aq) + H2O(l)

Chlorine change oxidation number from +1 to -1

Oxidation half reaction

(Cu+ ----------------------------------->Cu2+(aq) + e-)x2

Oxidatin number of copper change from +1 to +2

Overall reaction

2Cu+(aq) + ClO-(aq) + 2H+(aq)------------->2Cu2+(aq) + Cl-(aq)+ H2O(l)

2Cu2Cl2 (s) + HClO (aq) + H+(aq) ------->5Cl- (aq) +

2Cu2+ (aq) + H2O(l)