cube in expanded form [3/2x × + 1]
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Solution: (i) (2x + 1)³ ...
(a + b)³ = a³+ b³+ 3ab(a + b) (2x + 1)³ ...
= 8x³ + 1 + 12x² + 6x. (ii) (2a – 3b)³ ...
(a – b)³ = a³–b³ – 3ab(a – b) (2a – 3b)³ = (2a)³– (3b)³ – (3×2a×3b)(2a – 3b) ...
= 8a³–27b³–36a²b + 54ab² (iii) [3x/2 + 1]³ ...
(a + b)³ = a³+ b³+ 3ab(a + b) ...
= (27/8)x³ + (27/4) x² + 9/2 x + 1. ...
(a - b)³=a³-b³-3ab(a-b)
Step-by-step explanation:
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