Question

cube is 15cm
The length of a rectangle is 1cm mare
than its width and its sperimeter is 14.
cm, then the area of the rectangle
​

Answer 1

Answer:

★ Area = 12 cm² ★

Step-by-step explanation:

Given:

• Length of rectangle is 1 cm more than it's width
• Perimeter of rectangle is 14 cm.

To Find:

• What is the area of rectangle ?

Solution: Let the width of rectangle be x cm

∴ Length = (x + 1) cm

★ Perimeter of rectangle = 2 ( Length + Breadth ) ★

$\small\implies{\sf }$ 14 = 2 ( x + 1 + x )

$\small\implies{\sf }$ 14 = 2 ( 2x + 1 )

$\small\implies{\sf }$ 14 = 4x + 2

$\small\implies{\sf }$ 14 – 2 = 4x

$\small\implies{\sf }$ 12 = 4x

$\small\implies{\sf }$ 12/4 = x

$\small\implies{\sf }$ 3 = x

Hence, Width of rectangle is x = 3 cm and Length is (x + 1) = 3+1 = 4 cm

★ Area of Rectangle = Length x Breadth ★

→ Area = 3 x 4

→ 12 cm²

Answer 2

Given :

• Lenght of rectangle is 1 cm more than the breadth of the rectangle
• Perimeter of rectangle = 14 cm

To Find :

• Area of the rectangle

Solution :

Let's Breadth = x

Length = x + 1

$\tt Perimeter =2(l + b) \\ \\ \tt14 = 2(x + 1 + x) \\ \\ \tt14 =2(2x + 1) \\ \\ \tt 14 = 4x + 2 \\ \\\tt 4x = 14 - 2 \\ \\\tt 4x = 12 \\ \\\tt x = \frac{12}{4} \\ \\ \tt x = 3$

Breadth = 3 cm

Length = 3 + 1 = 4 cm

$\tt Area_{rectangle} = l \times b \\ \\ \implies \tt4 \times 3 \\ \\ \implies \tt12 \\ \\ \underline {\tt Area_{rectangle} = 12 \: {cm}^{2} }$