Math, asked by cocarchking, 12 hours ago

cube of side 6 cm is cut into 2 cm cubes. What is the ratio of the surface areas of the original cubes and cut-out cubes?

Answers

Answered by gokulkrish80
0

Answer:

9:1

Step-by-step explanation:

surface area of cube = 6*side*side

surface area of original cube = 6*6*6 = 256 square cm

surface area of new cube = 6*2*2 =24 square cm

Hence, Ratio of surface area of original cube to surface area of new cube =256:24 = 9:1

Answered by rehansjd156
0

Answer:

 \frac{6 \times  {6}^{2} }{6 \times  {2}^{2} }  =  \frac{216}{24}  = 9

9 cubes

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