cube root of 1+3+5+7.....+53 please explain
Answers
Answered by
6
Answer:
328509
Step-by-step explanation:
1+3+5+7+53=69
69^3=328509
Answered by
24
First we need number of terms in the series.
It is an arithmetic progression.
First term =1 . Common difference =2.
1 + (n-1) * 2 = 53.
》 2*(n-1) = 52.
》 n = 27.
Sum of natural odd number series
= n ^ 2
= 27^2.
Cube root = (27^2) ^(1/3)
=3 ^ ( 3 * 2 * 1/3 )
=3^2
=9.
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