cube root of 1.728 by prime factorization method
plz do in a paper by step by step explation by prime factorization method
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《《《《 The cube root of 1728 is ☆12☆ 》》》》
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♡♡REFER TO THE ATTACHMENT FOR EXPLANATION♡♡
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On prime factorising, we get,
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3)
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 =
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2 3 ×3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2 3 ×3 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2 3 ×3 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2 3 ×3 3
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2 3 ×3 3 =2×2×3=12.
On prime factorising, we get,1728=(2×2×2)×(2×2×2)×(3×3×3) =2 3 ×2 3 ×3 3 .Then, cube root of 1728 is:3 1728 = 3 2 3 ×2 3 ×3 3 =2×2×3=12.Therefore, 12 is the solution.
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