Question

cube root of 2 to the power of x-4 is equal to 16

Answer 1

Answer:

$\sqrt[3]{2^{x-4}} = 16$

$\Rightarrow 2^{x-4} = 16^3 = (2^4)^3 = 2^{12}$

$\Rightarrow x-4=12$

$\Rightarrow x = 12+4=16$