Math, asked by leosharad, 5 months ago

Cube root of (216)^-3÷(343)^-2​

Answers

Answered by harshittiwari92
0

Answer:

49/216

Step-by-step explanation:

(216)^-3÷(343)^-2

= 1/(216)^3 ÷ 1/(343)^2

= 1/(216)^3 × (343)^2 = 1/(216)^3 × (7^3)^2

= 1/(216)^3 × (7^2)^3 = (7^2)^3/(216)^3

= (49)^3/(216)^3

so Cube root of (216)^-3÷(343)^-2 = Cube root of (49)^3/(216)^3 = 49/216

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