Question

cube root of 2662 by prime factorisation

Answer 1

Given:

$\sqrt[3]{2662}$

We have to find, the value of $\sqrt[3]{2662}$ is:

Solution:

∴ $\sqrt[3]{2662}$

The prime factorisation of 2662

=  2 × 1331

= 2 × 11 × 121

= 2 × 11 × 11 × 11

∴ $\sqrt[3]{2\times 11\times 11\times 11}$

= 11$\sqrt[3]{2}$

∴ The value of $\sqrt[3]{2662}$ = 11$\sqrt[3]{2}$

Thus, the cube root of 2662 by prime factorisation is 11$\sqrt[3]{2}$.

Answer 2

Answer:

11 is the answer

mark as BRAINEST