Question

cube root of 3 ×[ cube root of x minus 1 by cube root of X] = 2 then cube root of x minus 1 by cube root of X is equals to?​

Answer 1

from LHS transpose cube root of 3 to RHS we get:

2/cube root of 3

the result

Answer 2

Answer:

8/3

Step-by-step explanation:

$\sqrt[3]{3} ( \sqrt[3]{x} - \frac{1}{ \sqrt[3]{x} } ) = 2$

$3( \sqrt[3]{x} - \frac{1}{ \sqrt[3]{x} } ) = {2}^{3}$

$\sqrt[3]{x} - \frac{1}{ \sqrt[3]{x} } = \frac{8}{3}$

therefore, the answer is

$\frac{8}{3}$

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