Math, asked by ashokeee742, 10 months ago

Cube root of 6 is irrational number prove

Answers

Answered by dhanu1312
1

Step-by-step explanation:

√6 is irrational because it is not a perfect cube of any number.....

Hope it helps u

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Answered by subhashnidevi4878
1

Answer:

\sqrt[3]{6}=1.84

Step-by-step explanation:

As we have to prove in the question that the cube root of 6 is an irrational number

We must prove it

As we have to prove in the question that the cube root of 6 is an irrational number

We must prove it

As we know that the definition of irrational numbers, These numbers are those numbers which cannot be written in the form of \dfrac{p}{q}

Hence as we have seen that above cube root of is not any perfect number and it is written in decimal form

Therefore it cannot be written in the form of tex]\dfrac{p}{q}[/tex]

Hence proved that cube root of 6 is an irrational number

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