Question

cube root of a + cobe root of b+ cube root of c =0 then ,a+b+c/3 the whole cube=?​

Answer 1

Step-by-step explanation:

Given, cube root a + cube root b + cube root c = 0

so, a^1/3 + b^1/3 = - c^1/3

=> (a^1/3 + b^1/3)^3 = (- c^1/3)^3

=> a + b + 3(a^1/3)(b^1/3)(a^1/3 + b^1/3) = - c

=> a + b + 3(a^1/3)(b^1/3)(- c^1/3) = - c

=> a + b - 3(a^1/3)(b^1/3)( c^1/3) = - c

=> a + b + c = 3(a^1/3)(b^1/3)( c^1/3)

=> (a + b + c)^3 = {3(a^1/3)(b^1/3)( c^1/3)}^3

=> (a + b + c)^3 = 27abc