Question

cube root of
$8 \times 10^{ - 12}$
and plzz how u have done it !! ​

Answer 1

$\sqrt[3]{8\times10^{-12} } \\ =( {8\times10^{-12}}) ^{\frac{1}{3}}\\ =(2^{3}^\times^\frac{1}{3})\times(10^{-12}^\times^\frac{1}{3})\\ =2\times10^{-4}$

Answer 2

Answer:

Step-by-step explanation:

( 8*10^(-12) )^(1/3) =

= 8^(1/3) * 10^(- 12/3)

= 2 * 10^(- 4)

= 0.0002