Question

(cube root of x) + (48/cube root of x) = 16
find value of x.​

Answer 1

Answer:

$\sqrt[3]{x} + 48 \div \sqrt[3]{x } = 16$

$48 \div \sqrt[3]{x} = 16 - \sqrt[3]{x}$

$\sqrt[3]{x} = (16 - \sqrt[3]{x} ) \times 48$

$\sqrt[3]{x} = 768 - 48 \sqrt[3]{x}$

$49 \sqrt[3]{x} = 768$

$\sqrt[3]{x} = 768 \div 49$=2.5025