CUBE ROOTS
1. Three numbers are in the ratio 1:2:3. The sums of their cubes are 7776. Find the
numbers
Answers
Answered by
2
Answer:
let the un known number be 'x'
1x+2x+3x=7776
6x=7776
x=7776÷6
x=1296
1x=1296
2x=2×1296=2592
3x=3×1296=3888
Explanation:
the answer is correct or not we can know by adding the answer
1296+2592+3888=7776
7776=7776
means answer is right
Answered by
0
Let the three no. be the multiple of x
Therefore, 1x, 2x, 3x
ATQ,
(1x)^3 + (2x)^3 + (3x)^3 = 7776
=> x^3 + 8x^3 + 27x^3 = 7776
=> 36x^3 =7776
=> x^3 = 7776/36
=> x^3 = 216
=> x = _/216
=> x = 6
Therefore, the nos. are:-
1; 1x = 6
2; 2x
2(6)= 12
3; 3x
3(6)= 18
Therefore, 1x, 2x, 3x
ATQ,
(1x)^3 + (2x)^3 + (3x)^3 = 7776
=> x^3 + 8x^3 + 27x^3 = 7776
=> 36x^3 =7776
=> x^3 = 7776/36
=> x^3 = 216
=> x = _/216
=> x = 6
Therefore, the nos. are:-
1; 1x = 6
2; 2x
2(6)= 12
3; 3x
3(6)= 18
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