Cubes each of volume 64cm^3are joined end to end.find surface area of resulting cuboid.
Please solve this question.......
Answers
Answered by
4
hey mate✌✌✌
here is your answer✍✍✍
64 cm^3 =volume
4 cm = side
length of resulting cuboid =3×4 =12 cm
bredth =4 cm
height =4 cm
TSA of cuboid
=2(12*4+4*4+12*4)
=2(48+16+48)
=2(112)
=224
hope it helps u....☺☺
here is your answer✍✍✍
64 cm^3 =volume
4 cm = side
length of resulting cuboid =3×4 =12 cm
bredth =4 cm
height =4 cm
TSA of cuboid
=2(12*4+4*4+12*4)
=2(48+16+48)
=2(112)
=224
hope it helps u....☺☺
yogesh1061:
what is this
Answered by
0
1st the side of cube whose volume is 64cm^3
a^3=64^3
a=4 cm
If we will join three cube of side 4cm than the length of resulted cuboid is 12 cm and height and breath will remain 4 cm
surface area of vubiod = 2(lb+bh+hl)
=2(12×4+4×4+4×12)
=2(48+16+48)
=2(112)
=224 cm^2
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