Question

Cubes of all even numbers are

Answer 1

Cubes of all even numbers are themselves even numbers. Let's check out the proof. Assume a general even number to be of the form 2n, where n is a whole number (n=0,1,2,3,...). This is true because all even numbers, by definition, are divisible by 2.
Now, cube of a general even number= 2n x 2n x 2n = 8n

Consider this new number obtained, 8n. This number is again divisible by 2 for any value of the whole number n. Thus, the cube of any even number is itself an even number.

Answer 2

Answer:

the cube of all even numbers are even only