Cubic equation ax3+bx+c$d=0 relation sum of zeros alpha beta gama
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Step-by-step explanation:
b) Let p(x) =ax3 + bx2 + cx + d
Given that, one of the zeroes of the cubic polynomial p(x) is zero.
Let α, β and γ are the zeroes of cubic polynomial p(x), where a = 0.
We know that,
then,
sum of product of zeroes = c/a
alpha × beta + beta× gamma + gmma × alpha = c/a
0 × beta + beta × gamma + gamma×0 =c/a
beta / gamma = c/a ..
Hence ,
The other two zeroes are c /a .
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