Question

cubical block weights 20 Newton in air and 10 Newton in water find the side of the cubical block ( g equals to 10 m/s ^2) ​

Answer 1

Answer:

ANSWER

Fraction of volume immersed before putting the new weight=ρwaterρblock

   =1000800

   =0.8

i.e., 20% of 3 cm or 0.6 cm is above water. Let W is the new weight, then spring will be compressed by 0.6 cm.

∴   W+weight of block=Upthrust on whole volume of block+spring force

or

W=(3×10−2)3×1000×10+50×(0.6×10−2)−(3×10−2)3×800×10

∴   W=0.354 N

Explanation:

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Answer 2

Answer:

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