Question

CUBOID : If length = 10 width=7.3
Height = 1.7, find surface Area
and volume​

Answer 1

$\bf\blue{Given -}$

$\huge\bf\pink{L=10}$

$\huge\bf\pink{W=7.3}$

$\huge\bf\pink{H=1.7}$

$\bf\blue{Find-}$

$\sf\pink{1.~Total~Surface~Area~of~Cubiod~(TSA)}$

And

$\sf\pink{2.~Volume~of~Cubiod}$

$\huge\sf\pink{Now ;}$

$\bf\green{1.~TSA~of~cubiod=2(lw+wh+lh)}$

putting values

$\bf\pink{=2(10×7.3+7.3×1.7+10×1.7)}$

$\bf\pink{=2(73+12.41+17)}$

$\bf\pink{=2(102.41)}$

$\bf\pink{=2×102.41}$

$\bf\pink{=204.82}$

$\therefore\sf\pink{TSA~of~Cubiod=204.82CM^2}$

$\sf\green{2.~Volume~of~Cubiod=l×w×h}$

$\huge\pink{10×7.3×1.7}$

$\huge\pink{124.1}$

$\therefore\sf\pink{Volume~of~Cobiod=124.1^3}$

Answer 2

Answer:

Given−

L=10

W=7.3

H=1.7

Find−

1. Total Surface Area of Cubiod (TSA)

And

2. Volume of Cubiod

Now;

1. TSA of cubiod=2(lw+wh+lh)

putting values

=2(10×7.3+7.3×1.7+10×1.7)

=2(73+12.41+17)

=2(102.41)

=2×102.41

=204.82

∴TSA of Cubiod=204.82CM

2. Volume of Cubiod=l×w×h

10×7.3×1.7

124.1

∴Volume of Cuboid =124.1³