Question

cuboid solid wooden block contains 189cm³ wood if it be 7cm long and 4.5cm high find its breadth please if you don't know answer please don't answer me ​

Answer 1

$\sf \bf \huge {\boxed {\mathbb {QUESTION}}}$

$\tt Cuboid\: solid \:wooden\: block\: contains\: 189\:{cm}^{3}\\\tt wood\: if \:it \:be\: 7\:cm \:long\: and\:4.5\:cm high \:find\\\tt its\: breadth$

$\sf \bf \huge {\boxed {\mathbb {ANSWER}}}$

$\sf \bf {\boxed {\mathbb {GIVEN}}}$

• $\sf \bf Volume \:of\:cuboidal \:block =189\:{cm}^{3}$
• $\sf \bf Length \:of\:cuboidal \:block =7\:cm$
• $\sf \bf Height \:of\:cuboidal \:block =4.5\:cm$

$\sf \bf {\boxed {\mathbb {TO\:FIND}}}$

• $\sf \bf Breadth \:of \:cuboidal \:block$

$\sf \bf {\boxed {\mathbb {SOLUTION}}}$

${\color {springgreen} \underline {\sf Breadth \:of \:the\:cuboidal \:block}}$

${\color {blue} {\boxed {\boxed {\boxed{ \color{green} {\sf \bf V = l \times b \times h}}}}}}$

• $\sf V=volume \:of \:cuboid$
• $\sf l=length \:of \:cuboid$
• $\sf b=breadth \:of \:cuboid$
• $\sf h=height \:of \:cuboid$

${\underbrace {\overbrace {\color {orange} {\bf Substitute \:the \:values}}}}$

$\sf \bf \implies 189=7 \times b \times 4.5$

$\sf \bf \implies 189=31.5 \times b$

$\sf \bf \implies b=\dfrac{189}{31.5}$

$\sf \bf \implies b=\dfrac{\cancel{189}}{\cancel{31.5}}$

$\implies {\color {lime} {\boxed {\boxed {\color {aqua} { \sf \bf b=6\:cm}}}}}$

${\underbrace {\color {red} {\overline {\color {red} {\underline {\color {red} {\sf \therefore The\:height \:of\:the \:cuboidal \:wooden \:block \:is\:6\:cm}}}}}}}$

$\sf \bf \huge {\boxed {\mathbb {HOPE \:IT \:HELPS \:YOU}}}$

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$\sf \bf \huge {\boxed {\mathbb {EXTRA\:INFORMATION}}}$

$\bf CSA \:of \:cuboid = 2(l+b)$

$\bf TSA \:of \:cuboid = 2(lb+bh+hl)$

$\bf Volume \:of \:cuboid = l \times b\times h$

Answer 2

Answer:

$⟹189=7×b×4.5</p><p></p><p> \\ \sf \bf \implies 189=31.5 \times b⟹189=31.5×b</p><p></p><p> \\ \sf \bf \implies b=\dfrac{189}{31.5}⟹b=31.5189</p><p></p><p> \\ \sf \bf \implies b=\dfrac{\cancel{189}}{\cancel{31.5}}⟹b=31.5189</p><p></p><p> \\ \implies {\color {lime} {\boxed {\boxed {\color {aqua} { \sf \bf b=6\:cm}}}}} \\ ⟹b=6cm</p><p></p><p> \\ {\underbrace {\color {red} {\overline {\color {red} {\underline {\color {red} {\sf \therefore The\:height \:of\:the \:cuboidal \:wooden \:block \:is\:6\:cm}}}}}}}∴ \\ The \: heigh \: to \: fthe \: cuboidal \: wooden \: block \: is \: 6cm</p><p></p><p></p><p>$