cubold. 2. Twenty cylindrical pillars of a building are to be cleaned. If the diameter of the pillar is 0.5m and height 4m, what will be cost of cleaning them at the rate of Rs.3 per m2
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The diameter of cylinder = 0.50 m (Given)
Therefore, radius =0.502m (As radius=Diameter2).
Radius(r) = 0.25 m
Height = 4 m (Given)
We know,
CSA of cylinder =2πrh
Substituting the values, we get:
2πrh=2×227×0.25×4
As; π=227r=0.25h=4
=2×227×25100×4
(To remove decimal)
=2×227
=447m2
CSA of 20 pillars =20×447m2
Calculating cost of cleaning:
It is given that cost of cleaning per m2 is Rs. 2.50, therefore cost of cleaning 20 pillars is given by:
CSA of 20 pillars x cost of cleaning per m2 =20×447×2.5 Rs.
= Rs. 314.28
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