Question

cucuit
This charge deposited on 4uf Capacitor the circuit
is
+
12 V
2 uf
6 uf
D 6X 10-6c
3 24 x 10-6-c
2) 12 x 10-6c
a) 25 x 10-6c​

Answer 1

Answer:

Explanation:

As the capacitors 4μF and 2μF are connected in parallel and are in series with 6μF capacitor, their equivalent capacitance is

(2+4)×62+4+6=3μF

Charge in the circuit,

Q=3μF×12V=36μC

image

Since, the capacitors 4μF and 2μF are connected in parallel, therefore potential difference across them is same.

⇒Q1Q2=C1C2=42

or Q1=2Q2

Also, Q=Q1+Q2

∴36μC=2Q2+Q2

or Q2=36μC3=12μC

Q1=Q−Q2=36μC−12μC

=24μC=24×10−6C