Question

cumple #13 10 15
A body of mass 10 kg is placed on a smooth Inclined plane as shown in figure. The inclined plane is moved with a horizontal acceleration a.

the normal reaction tension is ?and at what acceleration will the body lose contact with the inclined plane ?​

Answer 1

Answer:

A) normal reaction is mgcos∅ = 10*9.8*cos(37°) = 98*4/5 = 78.4N

B) tension in the thread is mgsin∅ = 10*9.8*sin(37°) = 58.8N

c) when moving with acceleration , the pseudo force will be ma so, for lifting of block the normal reaction should be 0.

now, Masin(37°) = Mgcos(37°)

==> a*3/5 = 10*4/5

=> a = 40/3 = 13.33 m/s²

Explanation:

here is your solution

Answer 2

Answer:

1.33 is your answer hope it is helpful