Question

CuO(s) + H2(g) Cu(s) + H2O(l) [3] In the above equation by giving reasons explain which substance is – (i) Oxidised (ii) Reduced​

Answer 1

Explanation:

i. H2 get oxidised to H2O

ii. CuO get reduced to Cu

Hope this will be helpful

Answer 2

Answer:

$oxidised \: this \: a \: correct \: answer \: guys$

$okay \: you \: understand \:$

$guys \:$

$this \: is \: a \: answer.$