Chemistry, asked by devansikedia20, 7 months ago

Cupric nitrate on strong heating decomposes as follows: 2 Cu(NO3)2 → 2CuO + 4NO2+ O2. If 37.4cupric nitrate is completely decomposed, calculate the mass of nitrogen dioxide liberated.

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Answered by premnath26

Answer:

Explanation:

Cupric nitrate on strong heating decomposes as follows: 2 Cu(NO3)2 → 2CuO + 4NO2+ O2. If 37.4cupric nitrate is completely decomposed, calculate the ma ...

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Cupric nitrate on strong heating decomposes as follows: 2 Cu(NO3)2 → 2CuO + 4NO2+ O2. If 37.4cupric nitrate is completely decomposed, calculate the mass of nitrogen dioxide liberated.​

Answers

Cupric nitrate on strong heating decomposes as follows: 2 Cu(NO3)2 → 2CuO + 4NO2+ O2. If 37.4cupric nitrate is completely decomposed, calculate the mass of nitrogen dioxide liberated.