Question

CUQThe straight line through A(a,b) intersects theline through B(c,d) at 'P' at right angles. Thelocus of P is1) (x-a)(x–c)+(y-b)(y-d)=02)(x-a)(x–c)-(y-b)(y-d)=03)(x-b)(x-d)+(y-a)(y-d)=0​

Answer 1

Answer:

As the line is passing through a, b and c, d the point P will be the right angle so, (x-a) 2 plus y minus b hole square =x minus c hole square + Y minus d hole square and solve......