Current 2 A is flowing through a conductor of resistance 8 Ω. The electrical energy consumed in 5 seconds is
Answers
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GIVEN DATA:-
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CURRENT = I = 2A
RESISTANCE = R = 8 OHM
REQUIRED :-
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ELECTRICAL ENERGY CONSUMED AT 5 SECOND =?
FORMULA :-
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ELECTRICAL ENERGY = POWER × TIME -------------1
POWER = I^2 × R
POWER = 2^2 × 8
POWER = 32 WATT
WE HAVE OBTAINED POWER NOW PUT THIS IN EQUATION 1
ELECTRICAL ENERGY = POWER × TIME
ELECTRICAL ENERGY = 32 × 5
ELECTRICAL ENERGY = 160 J
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SO ELECTRICAL ENERGY CONSUMED IS 160JOULE
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Answer:
The electrical energy consumed by the conductor in 5 seconds is equal to 160 Joules.
Explanation:
We have given,
The current flowing trough the conductor, I = 2A
The resistance of the conductor, R = 8Ω
The time for which energy consumed, Δt = 0
Calculate the power by using the formula given below:
P = I²R
P = (2A)²(8Ω)
P = 32 W
In an electric circuit, the energy consumed due to flow current through it is known as electrical energy.
The current flowing through the conductor with resistance R for time t is I, the electrical energy consumed to is Joules which is converted into heat energy.
Electrical energy = P.Δt
Substitute the value of power and time in above equation:
E = (32W).(5s)
E = 160 Ws
E = 160J [∵ 1 J/s = 1 Watt]
Therefore, the electrical energy consumed is equal to 160Joules.