Current carrying capacity of conductor if diameter of conductor halfed
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Explanation:
If the diameter is halved, the area becomes 1/8th times the initial area, therefore the currents carrying capacity increases 8 times the initial current carrying capacity.
Answered by
0
Answer:
Answer: 8 times the initial current carrying capacity
Explanation:
If the diameter is halved, the area becomes 1/8th times the initial area, therefore the currents carrying capacity increases 8 times the initial current carrying capacity.
R(resistance)= [(resistivity of conductor) * (length of wire)] / (area of cross section)
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