Question

CURRENT ELECTRICI
LEVEL-II
Two resistances of 5 ohm and 10 ohm are
connected in series. If the P.D. across 5 ohm
resistor is 10V, the heat developed in 2.1 sec
in the other resistor is :
1) 84 calories 2) 420 calories
3) 20 calories 4) 10 calories
R=
P
oh of 50W and 100V can​

Answer 1

Answer:

sorry

Explanation:

really don't know

Answer 2

Total resistance =10+5 =15ohm

so current passing through circuit

= V/R= 10/5=2 ampere

Here v = 10 and r=5

So Heat energy in other resistor is

H= I^2×R×T

H= 4 ×10×2.1

H=84 Joules

But in calories just divide H by 4.1 to get approx. 20 calories