Question

current flowing into wires A and B of same length is same when the same potential difference is applied across them if the conductivity of a is times to that of B then calculate the ratio of radii of cross section of the two wires.

please write the complete solution.
Don't write irrelevant answers that would be reported.
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Answer 1

resistance is given as

R = ρL/A

here ρ = resistivity of wire , L = length of wire , A = area of cross-section

clearly , resistance is directly propotional to length of wire

L₁ = length of one wire  , L₂ = length of one wire

R₁ = resistance of one wire , R₂ = resistance of one wire

so R₁/R₂ = L₁ / L₂

we have been given that ,  L₁ / L₂ = 2/1

so  R₁/R₂ = 2/1

V₁ = potential difference in one wire = V₂ = potential difference in other wire

i₁ R₁ = i₂ R₂

i₁ /i₂ = 1/(R₁/R₂)

i₁ /i₂ = 1/(2/1)

i₁ /i₂ = 1/2

so ratio of currents 1:2

I don't no whether answer is correct... I just tried... if wrong sorry

Answer 2

Answer:

The ratio is 1:2 .

Hope it's helpful...