Question

Current i=2.5 A flows along the circle x2+y2=9 cm2 (here x and y are in cm) . Magnetic field (in Tesla) at point (0,0,4 cm) is

Answer 1

Answer: 36 *3.14*10^-7

Explanation:

Answer 2

Answer:

The magnetic field is equal to 36π×10⁻⁷ Tesla at point (0,0,4cm).

Explanation:

Given that current $i=2.5A$

The current flows through circle $x^{2}+y^{2}=9cm^{2}$

Then $r=4cm=4*10^{-2}m$    (on z-axis)

When compare with equation of circle:

$R=\sqrt{9}cm^{2}=3*10^{-2}m$

Magnetic field,   $B=\frac{\mu _{o} i R^{2}}{2(Z^{2}+R^{2})^\frac{3}{2} }$

$B=\frac{(4\pi*10^{-7}*(2.5)*(3*10^{-2})^{2}) )}{2(3*10^{-2})^{2}+(4*10^{-2})^{2})^{\frac{3}{2}}}$

$B=\frac{4\pi *9*2.5*10^{-11}}{2*10^{-6}*125}$

$B=36\pi *10^{-7}$ Tesla

Therefore due to current  the magnetic field generated at given point  will be 36π×10⁻⁷ Tesla.