Question

current I flows through a long straight conductor which is bent into the circular loop of radius R in the middle as shown in the figure ​

Answer 1

option c is correct

by -biot savert law a force acting in center of any closed loop from which current is passed

in the centre of this loop magnetic field is equal to u0/2 *I/r

Answer 2

Given:

The current flowing is I

The radius of circular loop R

To find:

The resultant magnetic field at point O

Solution:

The formula of magnetic due to circular loop long wire.

B'=μ₀/2πR

For the magnetic field at loop point O

B"=μ₀l2πR/4πR² in upward direction

B"=μ₀l/2R

Now the net magnetic field at point O

B=B'+B"

B=μ₀I[π+1]/2πR

So, the option B is correct.