Question

current I in a circuit varies with time t as I=3+2t. calculate the current which would send the charge equivalent to the time interval t=0 to t=4s​

Answer 1

Explanation:

check the attachment

C-Integral constant

c-columb

Answer 2

Explanation:

Given:

I=4+2t

Let dq be the charge which passes in a small interval of time dt. Then

dq=Idt

or dq=(4+2t)dt

On integrating, we get

q=∫

2

6

(4+2t)dt=[4t+t

2

]

2

6

=48C

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