Question

current I in the network shown in figure ​

Answer 1

I is the net current. (phew)

10 + 6 in series => 16 ohms.

16 (10 + 6) and 16 in parallel => 8 ohms.

8 (10 + 6, 16) and 2 in series => 10 ohms.

Net resistance = 10 ohms.

EMF = 10 V.

Current = 10/10 A = 1 A.

Answer 2

Answer:

1A

Explanation:

see the attachment...