Question

Current I versus time t graph through a conductor is shown in the figure. Average current through the conductr in the interval 0 to 15 sec

Answer 1

Answer:

5A

Explanation:

The diagram which should have been there is attached.

If a graph is given, the average can be calculated by finding the area enclosed by the graph divided by the interval.

Here curve of current vs time is given. Graph of the current is triangular, area enclosed by it

= $\frac{1}{2}$ × 15 sec × 10 A (∵ Area of Δ = 1/2 × Base × Height)

= 75 A-sec

Time interval = 15 sec

∴ Average current = 75A-sec/15sec = 5A