Question

current in a coil increses from 0 to 1 ampere on 0.1second .if selfinductance of the coil is 4 milli henry ,magnitude of induced emf is​

Answer 1

Explanation:

ΔI = 1A

Δt = 0.1s

L = 4×10-³H

ε = ?

ε = L(ΔI/Δt )

ε = 4×10-³ (1/0.1)= 40mV