Physics, asked by aishusrini8685, 1 year ago

Current in coil fall from 5a-0a in 0.15. Calculate induced emf in that coil self inductance is 4h

Answers

Answered by manujgupta46

0

Answer:

self-induced emf = L di/ft

= 4 x 5/.10 = 200 V

here time is taken 0.1 s

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